Base | Representation |
---|---|
bin | 100111010111111001100… |
… | …0010010101001010100011 |
3 | 201011022212122111202121201 |
4 | 1032233303002111022203 |
5 | 1202130112433101011 |
6 | 15301552023302031 |
7 | 1065651363052246 |
oct | 116576302251243 |
9 | 21138778452551 |
10 | 5411441300131 |
11 | 17a6a855a0aa9 |
12 | 7349348aa917 |
13 | 3033b1b9ba89 |
14 | 149cb529125d |
15 | 95b6d7c9cc1 |
hex | 4ebf30952a3 |
5411441300131 has 2 divisors, whose sum is σ = 5411441300132. Its totient is φ = 5411441300130.
The previous prime is 5411441299997. The next prime is 5411441300137. The reversal of 5411441300131 is 1310031441145.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5411441300131 - 213 = 5411441291939 is a prime.
It is a super-2 number, since 2×54114413001312 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5411441300131.
It is not a weakly prime, because it can be changed into another prime (5411441300137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2705720650065 + 2705720650066.
It is an arithmetic number, because the mean of its divisors is an integer number (2705720650066).
Almost surely, 25411441300131 is an apocalyptic number.
5411441300131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5411441300131 is an equidigital number, since it uses as much as digits as its factorization.
5411441300131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 5411441300131 its reverse (1310031441145), we get a palindrome (6721472741276).
The spelling of 5411441300131 in words is "five trillion, four hundred eleven billion, four hundred forty-one million, three hundred thousand, one hundred thirty-one".
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