Base | Representation |
---|---|
bin | 110010011001100001… |
… | …100110100001101001 |
3 | 12011200101112121022011 |
4 | 302121201212201221 |
5 | 1341312011031103 |
6 | 40505451155521 |
7 | 3624012500563 |
oct | 623141464151 |
9 | 164611477264 |
10 | 54115330153 |
11 | 20a4a769555 |
12 | a5a3145ba1 |
13 | 5145541921 |
14 | 2895106333 |
15 | 161acebd6d |
hex | c99866869 |
54115330153 has 2 divisors, whose sum is σ = 54115330154. Its totient is φ = 54115330152.
The previous prime is 54115330133. The next prime is 54115330237. The reversal of 54115330153 is 35103351145.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 48359528464 + 5755801689 = 219908^2 + 75867^2 .
It is a cyclic number.
It is not a de Polignac number, because 54115330153 - 233 = 45525395561 is a prime.
It is not a weakly prime, because it can be changed into another prime (54115330103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27057665076 + 27057665077.
It is an arithmetic number, because the mean of its divisors is an integer number (27057665077).
Almost surely, 254115330153 is an apocalyptic number.
It is an amenable number.
54115330153 is a deficient number, since it is larger than the sum of its proper divisors (1).
54115330153 is an equidigital number, since it uses as much as digits as its factorization.
54115330153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 54115330153 its reverse (35103351145), we get a palindrome (89218681298).
The spelling of 54115330153 in words is "fifty-four billion, one hundred fifteen million, three hundred thirty thousand, one hundred fifty-three".
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