Base | Representation |
---|---|
bin | 100111011000110010001… |
… | …0010110000111001011001 |
3 | 201011111210001221112111012 |
4 | 1032301210102300321121 |
5 | 1202143010401332213 |
6 | 15302504341543305 |
7 | 1066046434655423 |
oct | 116614422607131 |
9 | 21144701845435 |
10 | 5413341433433 |
11 | 17a78701282aa |
12 | 735185114b35 |
13 | 30362574b1cb |
14 | 14a015791813 |
15 | 95c305124a8 |
hex | 4ec644b0e59 |
5413341433433 has 4 divisors (see below), whose sum is σ = 5413349768628. Its totient is φ = 5413333098240.
The previous prime is 5413341433387. The next prime is 5413341433447. The reversal of 5413341433433 is 3343341433145.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2089837423129 + 3323504010304 = 1445627^2 + 1823048^2 .
It is a cyclic number.
It is not a de Polignac number, because 5413341433433 - 26 = 5413341433369 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5413341433453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3102716 + ... + 4522557.
It is an arithmetic number, because the mean of its divisors is an integer number (1353337442157).
Almost surely, 25413341433433 is an apocalyptic number.
It is an amenable number.
5413341433433 is a deficient number, since it is larger than the sum of its proper divisors (8335195).
5413341433433 is an equidigital number, since it uses as much as digits as its factorization.
5413341433433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8335194.
The product of its digits is 933120, while the sum is 41.
Adding to 5413341433433 its reverse (3343341433145), we get a palindrome (8756682866578).
The spelling of 5413341433433 in words is "five trillion, four hundred thirteen billion, three hundred forty-one million, four hundred thirty-three thousand, four hundred thirty-three".
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