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5413351245073 is a prime number
BaseRepresentation
bin100111011000110010011…
…1000001100010100010001
3201011111210202102000112021
41032301210320030110101
51202143020404320243
615302505332131441
71066046614241662
oct116614470142421
921144722360467
105413351245073
1117a78757199a2
12735188466b81
133036277a5105
1414a016bc7369
1595c312ee6ed
hex4ec64e0c511

5413351245073 has 2 divisors, whose sum is σ = 5413351245074. Its totient is φ = 5413351245072.

The previous prime is 5413351244981. The next prime is 5413351245101. The reversal of 5413351245073 is 3705421533145.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4615914747024 + 797436498049 = 2148468^2 + 892993^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5413351245073 is a prime.

It is not a weakly prime, because it can be changed into another prime (5413351245373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2706675622536 + 2706675622537.

It is an arithmetic number, because the mean of its divisors is an integer number (2706675622537).

Almost surely, 25413351245073 is an apocalyptic number.

It is an amenable number.

5413351245073 is a deficient number, since it is larger than the sum of its proper divisors (1).

5413351245073 is an equidigital number, since it uses as much as digits as its factorization.

5413351245073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756000, while the sum is 43.

The spelling of 5413351245073 in words is "five trillion, four hundred thirteen billion, three hundred fifty-one million, two hundred forty-five thousand, seventy-three".