Base | Representation |
---|---|
bin | 110010011010111111… |
… | …011011011000111001 |
3 | 12011202002211012120011 |
4 | 302122333123120321 |
5 | 1341334310113243 |
6 | 40512130301521 |
7 | 3624431531032 |
oct | 623277333071 |
9 | 164662735504 |
10 | 54139926073 |
11 | 20a62638862 |
12 | a5ab4278a1 |
13 | 514a673c1c |
14 | 28984a9a89 |
15 | 161d05989d |
hex | c9afdb639 |
54139926073 has 2 divisors, whose sum is σ = 54139926074. Its totient is φ = 54139926072.
The previous prime is 54139926053. The next prime is 54139926083. The reversal of 54139926073 is 37062993145.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29877813904 + 24262112169 = 172852^2 + 155763^2 .
It is a cyclic number.
It is not a de Polignac number, because 54139926073 - 217 = 54139795001 is a prime.
It is a super-2 number, since 2×541399260732 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (54139926053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27069963036 + 27069963037.
It is an arithmetic number, because the mean of its divisors is an integer number (27069963037).
Almost surely, 254139926073 is an apocalyptic number.
It is an amenable number.
54139926073 is a deficient number, since it is larger than the sum of its proper divisors (1).
54139926073 is an equidigital number, since it uses as much as digits as its factorization.
54139926073 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1224720, while the sum is 49.
The spelling of 54139926073 in words is "fifty-four billion, one hundred thirty-nine million, nine hundred twenty-six thousand, seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •