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54141154403 = 77734450629
BaseRepresentation
bin110010011011000100…
…000111010001100011
312011202012010121111212
4302123010013101203
51341340113420103
640512212500335
73624445135130
oct623304072143
9164665117455
1054141154403
1120a632a7706
12a5ab91a6ab
13514a9b404b
142898709587
15161d1ed7d8
hexc9b107463

54141154403 has 4 divisors (see below), whose sum is σ = 61875605040. Its totient is φ = 46406703768.

The previous prime is 54141154393. The next prime is 54141154423. The reversal of 54141154403 is 30445114145.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 54141154403 - 224 = 54124377187 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 54141154403.

It is not an unprimeable number, because it can be changed into a prime (54141154423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3867225308 + ... + 3867225321.

It is an arithmetic number, because the mean of its divisors is an integer number (15468901260).

Almost surely, 254141154403 is an apocalyptic number.

54141154403 is a deficient number, since it is larger than the sum of its proper divisors (7734450637).

54141154403 is an equidigital number, since it uses as much as digits as its factorization.

54141154403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7734450636.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 54141154403 its reverse (30445114145), we get a palindrome (84586268548).

The spelling of 54141154403 in words is "fifty-four billion, one hundred forty-one million, one hundred fifty-four thousand, four hundred three".

Divisors: 1 7 7734450629 54141154403