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5414344015001 is a prime number
BaseRepresentation
bin100111011001010000000…
…0011010011110010011001
3201011121100221110221211212
41032302200003103302121
51202202034031440001
615303152034432505
71066113330530645
oct116624003236231
921147327427755
105414344015001
1117a8235054709
12735404a32735
1330375538043c
1414a0ac9b1c25
1595c8d5537bb
hex4eca00d3c99

5414344015001 has 2 divisors, whose sum is σ = 5414344015002. Its totient is φ = 5414344015000.

The previous prime is 5414344014997. The next prime is 5414344015009. The reversal of 5414344015001 is 1005104434145.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5271593040025 + 142750974976 = 2295995^2 + 377824^2 .

It is a cyclic number.

It is not a de Polignac number, because 5414344015001 - 22 = 5414344014997 is a prime.

It is a super-2 number, since 2×54143440150012 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5414344015009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2707172007500 + 2707172007501.

It is an arithmetic number, because the mean of its divisors is an integer number (2707172007501).

Almost surely, 25414344015001 is an apocalyptic number.

It is an amenable number.

5414344015001 is a deficient number, since it is larger than the sum of its proper divisors (1).

5414344015001 is an equidigital number, since it uses as much as digits as its factorization.

5414344015001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 5414344015001 its reverse (1005104434145), we get a palindrome (6419448449146).

The spelling of 5414344015001 in words is "five trillion, four hundred fourteen billion, three hundred forty-four million, fifteen thousand, one".