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5414351912161 = 10495161441289
BaseRepresentation
bin100111011001010000010…
…0001011011110011100001
3201011121101111100011201021
41032302200201123303201
51202202043042142121
615303152520005441
71066113454621513
oct116624041336341
921147344304637
105414351912161
1117a8239558995
12735407600881
13303756bb6b0a
1414a0ada69bb3
1595c8e0b3641
hex4eca085bce1

5414351912161 has 4 divisors (see below), whose sum is σ = 5419513354500. Its totient is φ = 5409190469824.

The previous prime is 5414351912129. The next prime is 5414351912191. The reversal of 5414351912161 is 1612191534145.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5164851662161 + 249500250000 = 2272631^2 + 499500^2 .

It is a cyclic number.

It is not a de Polignac number, because 5414351912161 - 25 = 5414351912129 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5414351912111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2580719596 + ... + 2580721693.

It is an arithmetic number, because the mean of its divisors is an integer number (1354878338625).

Almost surely, 25414351912161 is an apocalyptic number.

It is an amenable number.

5414351912161 is a deficient number, since it is larger than the sum of its proper divisors (5161442339).

5414351912161 is a wasteful number, since it uses less digits than its factorization.

5414351912161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5161442338.

The product of its digits is 129600, while the sum is 43.

The spelling of 5414351912161 in words is "five trillion, four hundred fourteen billion, three hundred fifty-one million, nine hundred twelve thousand, one hundred sixty-one".

Divisors: 1 1049 5161441289 5414351912161