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541525432001 is a prime number
BaseRepresentation
bin1111110000101010110…
…11100101011011000001
31220202202211122020001112
413320111123211123001
532333021002311001
61052435013213105
754060335136641
oct7702533453301
91822684566045
10541525432001
11199728a97144
1288b4b931195
133c0b1258308
141c2d2234521
15e1464d9cbb
hex7e156e56c1

541525432001 has 2 divisors, whose sum is σ = 541525432002. Its totient is φ = 541525432000.

The previous prime is 541525431991. The next prime is 541525432037. The reversal of 541525432001 is 100234525145.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 287510440000 + 254014992001 = 536200^2 + 503999^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-541525432001 is a prime.

It is a super-3 number, since 3×5415254320013 (a number of 36 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (541525432081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270762716000 + 270762716001.

It is an arithmetic number, because the mean of its divisors is an integer number (270762716001).

Almost surely, 2541525432001 is an apocalyptic number.

It is an amenable number.

541525432001 is a deficient number, since it is larger than the sum of its proper divisors (1).

541525432001 is an equidigital number, since it uses as much as digits as its factorization.

541525432001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24000, while the sum is 32.

Adding to 541525432001 its reverse (100234525145), we get a palindrome (641759957146).

The spelling of 541525432001 in words is "five hundred forty-one billion, five hundred twenty-five million, four hundred thirty-two thousand, one".