Base | Representation |
---|---|
bin | 111101100100110100101100… |
… | …1001000111011111001110001 |
3 | 2122000201121201010110120220202 |
4 | 1323021221121020323321301 |
5 | 1031442421132141002423 |
6 | 5155534001221244545 |
7 | 222040641652050200 |
oct | 17311513110737161 |
9 | 2560647633416822 |
10 | 541622641344113 |
11 | 147639965a6926a |
12 | 508b611a863755 |
13 | 1a32aa46849604 |
14 | 97a696622d237 |
15 | 4293cab7b5728 |
hex | 1ec9a5923be71 |
541622641344113 has 12 divisors (see below), whose sum is σ = 630066070380852. Its totient is φ = 464236746835680.
The previous prime is 541622641344107. The next prime is 541622641344157. The reversal of 541622641344113 is 311443146226145.
It can be written as a sum of positive squares in 2 ways, for example, as 333241666088464 + 208380975255649 = 18254908^2 + 14435407^2 .
It is not a de Polignac number, because 541622641344113 - 24 = 541622641344097 is a prime.
It is not an unprimeable number, because it can be changed into a prime (541622641344193) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 131661470 + ... + 135712887.
It is an arithmetic number, because the mean of its divisors is an integer number (52505505865071).
Almost surely, 2541622641344113 is an apocalyptic number.
It is an amenable number.
541622641344113 is a deficient number, since it is larger than the sum of its proper divisors (88443429036739).
541622641344113 is a wasteful number, since it uses less digits than its factorization.
541622641344113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 267415712 (or 267415705 counting only the distinct ones).
The product of its digits is 1658880, while the sum is 47.
The spelling of 541622641344113 in words is "five hundred forty-one trillion, six hundred twenty-two billion, six hundred forty-one million, three hundred forty-four thousand, one hundred thirteen".
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