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542003111500243 = 624786762143669
BaseRepresentation
bin111101100111100101110111…
…0111011011001100111010011
32122002001222202202012002121211
41323033023232323121213103
51032020134333021001433
65200424443025200551
7222110301241032661
oct17317135673314723
92562058682162554
10542003111500243
111477762574a4928
1250957a01490157
131a35789c016203
1497bb13a733c31
15429db288638cd
hex1ecf2eeed99d3

542003111500243 has 4 divisors (see below), whose sum is σ = 542089873650160. Its totient is φ = 541916349350328.

The previous prime is 542003111500199. The next prime is 542003111500261. The reversal of 542003111500243 is 342005111300245.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-542003111500243 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (542003111500043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43381065588 + ... + 43381078081.

It is an arithmetic number, because the mean of its divisors is an integer number (135522468412540).

Almost surely, 2542003111500243 is an apocalyptic number.

542003111500243 is a deficient number, since it is larger than the sum of its proper divisors (86762149917).

542003111500243 is an equidigital number, since it uses as much as digits as its factorization.

542003111500243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 86762149916.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 542003111500243 its reverse (342005111300245), we get a palindrome (884008222800488).

The spelling of 542003111500243 in words is "five hundred forty-two trillion, three billion, one hundred eleven million, five hundred thousand, two hundred forty-three".

Divisors: 1 6247 86762143669 542003111500243