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54201403 is a prime number
BaseRepresentation
bin1100111011000…
…0110000111011
310202222201100101
43032300300323
5102333421103
65213420231
71225463404
oct316606073
9122881311
1054201403
1128660353
121619a677
13b2c9849
1472ac9ab
154b59a1d
hex33b0c3b

54201403 has 2 divisors, whose sum is σ = 54201404. Its totient is φ = 54201402.

The previous prime is 54201397. The next prime is 54201437. The reversal of 54201403 is 30410245.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-54201403 is a prime.

It is not a weakly prime, because it can be changed into another prime (54201443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27100701 + 27100702.

It is an arithmetic number, because the mean of its divisors is an integer number (27100702).

Almost surely, 254201403 is an apocalyptic number.

54201403 is a deficient number, since it is larger than the sum of its proper divisors (1).

54201403 is an equidigital number, since it uses as much as digits as its factorization.

54201403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 19.

The square root of 54201403 is about 7362.1602128723. The cubic root of 54201403 is about 378.4456428568.

Adding to 54201403 its reverse (30410245), we get a palindrome (84611648).

The spelling of 54201403 in words is "fifty-four million, two hundred one thousand, four hundred three".