Base | Representation |
---|---|
bin | 100111011011111110111… |
… | …0001011001110011010010 |
3 | 201012011111211220021202011 |
4 | 1032313331301121303102 |
5 | 1202301043101043032 |
6 | 15310002152013134 |
7 | 1066411614163051 |
oct | 116677561316322 |
9 | 21164454807664 |
10 | 5420211346642 |
11 | 17aa776000824 |
12 | 7365819911aa |
13 | 30417bb08001 |
14 | 14a4a7d28398 |
15 | 95ed36d2247 |
hex | 4edfdc59cd2 |
5420211346642 has 4 divisors (see below), whose sum is σ = 8130317019966. Its totient is φ = 2710105673320.
The previous prime is 5420211346637. The next prime is 5420211346663. The reversal of 5420211346642 is 2466431120245.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 4724923868721 + 695287477921 = 2173689^2 + 833839^2 .
It is a Smith number, since the sum of its digits (40) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a junction number, because it is equal to n+sod(n) for n = 5420211346595 and 5420211346604.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1355052836659 + ... + 1355052836662.
Almost surely, 25420211346642 is an apocalyptic number.
5420211346642 is a deficient number, since it is larger than the sum of its proper divisors (2710105673324).
5420211346642 is a wasteful number, since it uses less digits than its factorization.
5420211346642 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2710105673323.
The product of its (nonzero) digits is 276480, while the sum is 40.
Adding to 5420211346642 its reverse (2466431120245), we get a palindrome (7886642466887).
The spelling of 5420211346642 in words is "five trillion, four hundred twenty billion, two hundred eleven million, three hundred forty-six thousand, six hundred forty-two".
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