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5421021171403 = 79317216468521
BaseRepresentation
bin100111011100010111000…
…0010101000111011001011
3201012020121021201122110211
41032320232002220323023
51202304222404441103
615310214401221551
71066440646446145
oct116705602507313
921166537648424
105421021171403
111800051142092
127367690318b7
1330427a81aa66
1414a5436cdc95
159602e84a36d
hex4ee2e0a8ecb

5421021171403 has 8 divisors (see below), whose sum is σ = 5506959199680. Its totient is φ = 5335516080960.

The previous prime is 5421021171323. The next prime is 5421021171413. The reversal of 5421021171403 is 3041711201245.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-5421021171403 is a prime.

It is not an unprimeable number, because it can be changed into a prime (5421021171413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 108209218 + ... + 108259303.

It is an arithmetic number, because the mean of its divisors is an integer number (688369899960).

Almost surely, 25421021171403 is an apocalyptic number.

5421021171403 is a deficient number, since it is larger than the sum of its proper divisors (85938028277).

5421021171403 is a wasteful number, since it uses less digits than its factorization.

5421021171403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 216468917.

The product of its (nonzero) digits is 6720, while the sum is 31.

Adding to 5421021171403 its reverse (3041711201245), we get a palindrome (8462732372648).

The spelling of 5421021171403 in words is "five trillion, four hundred twenty-one billion, twenty-one million, one hundred seventy-one thousand, four hundred three".

Divisors: 1 79 317 25043 216468521 17101013159 68620521157 5421021171403