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54220440251361 = 318073480083787
BaseRepresentation
bin11000101010000001011100…
…00101001010101111100001
321002222102102201002000011010
430111000232011022233201
524101321430201020421
6311152305411011133
714264204024562636
oct1425005605125741
9232872381060133
1054220440251361
1116304839aa827a
1260b834b899aa9
132433c724aab67
14d563d759218d
156405e87c0076
hex31502e14abe1

54220440251361 has 4 divisors (see below), whose sum is σ = 72293920335152. Its totient is φ = 36146960167572.

The previous prime is 54220440251359. The next prime is 54220440251443. The reversal of 54220440251361 is 16315204402245.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 54220440251361 - 21 = 54220440251359 is a prime.

It is a super-2 number, since 2×542204402513612 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (54220440255361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9036740041891 + ... + 9036740041896.

It is an arithmetic number, because the mean of its divisors is an integer number (18073480083788).

Almost surely, 254220440251361 is an apocalyptic number.

It is an amenable number.

54220440251361 is a deficient number, since it is larger than the sum of its proper divisors (18073480083791).

54220440251361 is a wasteful number, since it uses less digits than its factorization.

54220440251361 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18073480083790.

The product of its (nonzero) digits is 230400, while the sum is 39.

The spelling of 54220440251361 in words is "fifty-four trillion, two hundred twenty billion, four hundred forty million, two hundred fifty-one thousand, three hundred sixty-one".

Divisors: 1 3 18073480083787 54220440251361