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5422125104153 is a prime number
BaseRepresentation
bin100111011100110111111…
…0101110011110000011001
3201012100110012222020111222
41032321233311303300121
51202314003011313103
615310520114301425
71066510212642032
oct116715765636031
921170405866458
105422125104153
1118005682a30aa
12736a16887875
133043c54477c4
1414a60a173a89
159609670b638
hex4ee6fd73c19

5422125104153 has 2 divisors, whose sum is σ = 5422125104154. Its totient is φ = 5422125104152.

The previous prime is 5422125104141. The next prime is 5422125104219. The reversal of 5422125104153 is 3514015212245.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4559775141769 + 862349962384 = 2135363^2 + 928628^2 .

It is a cyclic number.

It is not a de Polignac number, because 5422125104153 - 220 = 5422124055577 is a prime.

It is a super-3 number, since 3×54221251041533 (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (5422125104453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2711062552076 + 2711062552077.

It is an arithmetic number, because the mean of its divisors is an integer number (2711062552077).

Almost surely, 25422125104153 is an apocalyptic number.

It is an amenable number.

5422125104153 is a deficient number, since it is larger than the sum of its proper divisors (1).

5422125104153 is an equidigital number, since it uses as much as digits as its factorization.

5422125104153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48000, while the sum is 35.

The spelling of 5422125104153 in words is "five trillion, four hundred twenty-two billion, one hundred twenty-five million, one hundred four thousand, one hundred fifty-three".