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542435032411313 is a prime number
BaseRepresentation
bin111101101010101110111111…
…1011010111010110010110001
32122010121021122001120202121012
41323111131333122322302301
51032044223421244130223
65201355114101240305
7222153431526144446
oct17325357732726261
92563537561522535
10542435032411313
111479224505a9168
1250a07662a03095
131a3895339921c2
1497d3dd20cd9cd
1542a9ea7824c78
hex1ed577f6bacb1

542435032411313 has 2 divisors, whose sum is σ = 542435032411314. Its totient is φ = 542435032411312.

The previous prime is 542435032411291. The next prime is 542435032411387. The reversal of 542435032411313 is 313114230534245.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 511892797002304 + 30542235409009 = 22625048^2 + 5526503^2 .

It is a cyclic number.

It is not a de Polignac number, because 542435032411313 - 210 = 542435032410289 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (542435032401313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271217516205656 + 271217516205657.

It is an arithmetic number, because the mean of its divisors is an integer number (271217516205657).

Almost surely, 2542435032411313 is an apocalyptic number.

It is an amenable number.

542435032411313 is a deficient number, since it is larger than the sum of its proper divisors (1).

542435032411313 is an equidigital number, since it uses as much as digits as its factorization.

542435032411313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 542435032411313 its reverse (313114230534245), we get a palindrome (855549262945558).

The spelling of 542435032411313 in words is "five hundred forty-two trillion, four hundred thirty-five billion, thirty-two million, four hundred eleven thousand, three hundred thirteen".