Base | Representation |
---|---|
bin | 1111110010100000011… |
… | …11000011100101110001 |
3 | 1220212022121001020122111 |
4 | 13321100033003211301 |
5 | 32342031033102231 |
6 | 1053120535005321 |
7 | 54123644641342 |
oct | 7712017034561 |
9 | 1825277036574 |
10 | 542512003441 |
11 | 19a094978941 |
12 | 89186209841 |
13 | 3c20a7731b5 |
14 | 1c3872880c9 |
15 | e1a2e174b1 |
hex | 7e503c3971 |
542512003441 has 4 divisors (see below), whose sum is σ = 571065266800. Its totient is φ = 513958740084.
The previous prime is 542512003433. The next prime is 542512003463. The reversal of 542512003441 is 144300215245.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 542512003441 - 23 = 542512003433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (542512003471) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14276631651 + ... + 14276631688.
It is an arithmetic number, because the mean of its divisors is an integer number (142766316700).
Almost surely, 2542512003441 is an apocalyptic number.
It is an amenable number.
542512003441 is a deficient number, since it is larger than the sum of its proper divisors (28553263359).
542512003441 is a wasteful number, since it uses less digits than its factorization.
542512003441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28553263358.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 542512003441 its reverse (144300215245), we get a palindrome (686812218686).
The spelling of 542512003441 in words is "five hundred forty-two billion, five hundred twelve million, three thousand, four hundred forty-one".
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