Base | Representation |
---|---|
bin | 111101101111001001101011… |
… | …1100010101110001000011001 |
3 | 2122012202022120201200112120002 |
4 | 1323132103113202232020121 |
5 | 1032134200210404142340 |
6 | 5202542033005142345 |
7 | 222245332335100460 |
oct | 17336232742561031 |
9 | 2565668521615502 |
10 | 543042101240345 |
11 | 148036953087623 |
12 | 50aa5244b5a9b5 |
13 | 1a40185bc74185 |
14 | 98155410c99d7 |
15 | 42bab88055715 |
hex | 1ede4d78ae219 |
543042101240345 has 32 divisors (see below), whose sum is σ = 762920446014720. Its totient is φ = 363283528181760.
The previous prime is 543042101240333. The next prime is 543042101240377.
543042101240345 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 543042101240345 - 224 = 543042084463129 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 543042101240299 and 543042101240308.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 85254566 + ... + 91402544.
It is an arithmetic number, because the mean of its divisors is an integer number (23841263937960).
Almost surely, 2543042101240345 is an apocalyptic number.
It is an amenable number.
543042101240345 is a deficient number, since it is larger than the sum of its proper divisors (219878344774375).
543042101240345 is a wasteful number, since it uses less digits than its factorization.
543042101240345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6209585.
The product of its (nonzero) digits is 230400, while the sum is 38.
It can be divided in two parts, 54304210 and 1240345, that added together give a palindrome (55544555).
The spelling of 543042101240345 in words is "five hundred forty-three trillion, forty-two billion, one hundred one million, two hundred forty thousand, three hundred forty-five".
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