Base | Representation |
---|---|
bin | 11000101100101000010001… |
… | …11111111011011110110001 |
3 | 21010021222122010221100200002 |
4 | 30112110020333323132301 |
5 | 24104303401140344403 |
6 | 311301401505435345 |
7 | 14303524510560404 |
oct | 1426241077733661 |
9 | 233258563840602 |
10 | 54310012434353 |
11 | 16339824184095 |
12 | 611178933bb55 |
13 | 243c54879c380 |
14 | d5a893727d3b |
15 | 642adc2e1188 |
hex | 316508ffb7b1 |
54310012434353 has 16 divisors (see below), whose sum is σ = 58548283428096. Its totient is φ = 50080413611520.
The previous prime is 54310012434313. The next prime is 54310012434383. The reversal of 54310012434353 is 35343421001345.
It is a cyclic number.
It is not a de Polignac number, because 54310012434353 - 216 = 54310012368817 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54310012434313) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 71749025 + ... + 72502017.
It is an arithmetic number, because the mean of its divisors is an integer number (3659267714256).
Almost surely, 254310012434353 is an apocalyptic number.
It is an amenable number.
54310012434353 is a deficient number, since it is larger than the sum of its proper divisors (4238270993743).
54310012434353 is a wasteful number, since it uses less digits than its factorization.
54310012434353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 758744.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 54310012434353 its reverse (35343421001345), we get a palindrome (89653433435698).
The spelling of 54310012434353 in words is "fifty-four trillion, three hundred ten billion, twelve million, four hundred thirty-four thousand, three hundred fifty-three".
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