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54310444481 is a prime number
BaseRepresentation
bin110010100101001001…
…111001110111000001
312012011222200102211202
4302211021321313001
51342211433210411
640541101150545
73631602106166
oct624511716701
9165158612752
1054310444481
112103a914867
12a63855b455
135176aa81a7
1428b2db606d
15162cedd83b
hexca5279dc1

54310444481 has 2 divisors, whose sum is σ = 54310444482. Its totient is φ = 54310444480.

The previous prime is 54310444471. The next prime is 54310444501. The reversal of 54310444481 is 18444401345.

54310444481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31323336256 + 22987108225 = 176984^2 + 151615^2 .

It is a cyclic number.

It is not a de Polignac number, because 54310444481 - 210 = 54310443457 is a prime.

It is a super-3 number, since 3×543104444813 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (54310444411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27155222240 + 27155222241.

It is an arithmetic number, because the mean of its divisors is an integer number (27155222241).

Almost surely, 254310444481 is an apocalyptic number.

It is an amenable number.

54310444481 is a deficient number, since it is larger than the sum of its proper divisors (1).

54310444481 is an equidigital number, since it uses as much as digits as its factorization.

54310444481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 122880, while the sum is 38.

The spelling of 54310444481 in words is "fifty-four billion, three hundred ten million, four hundred forty-four thousand, four hundred eighty-one".