Base | Representation |
---|---|
bin | 110010100101011111… |
… | …000100111110011001 |
3 | 12012012101010102202202 |
4 | 302211133010332121 |
5 | 1342214343320113 |
6 | 40541420135545 |
7 | 3632000224436 |
oct | 624537047631 |
9 | 165171112682 |
10 | 54315995033 |
11 | 21042a65aa3 |
12 | a63a3975b5 |
13 | 5177c9c741 |
14 | 28b3a1cb8d |
15 | 162d738258 |
hex | ca57c4f99 |
54315995033 has 2 divisors, whose sum is σ = 54315995034. Its totient is φ = 54315995032.
The previous prime is 54315995011. The next prime is 54315995051. The reversal of 54315995033 is 33059951345.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 46127011984 + 8188983049 = 214772^2 + 90493^2 .
It is a cyclic number.
It is not a de Polignac number, because 54315995033 - 216 = 54315929497 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (54315995003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27157997516 + 27157997517.
It is an arithmetic number, because the mean of its divisors is an integer number (27157997517).
Almost surely, 254315995033 is an apocalyptic number.
It is an amenable number.
54315995033 is a deficient number, since it is larger than the sum of its proper divisors (1).
54315995033 is an equidigital number, since it uses as much as digits as its factorization.
54315995033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1093500, while the sum is 47.
The spelling of 54315995033 in words is "fifty-four billion, three hundred fifteen million, nine hundred ninety-five thousand, thirty-three".
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