Base | Representation |
---|---|
bin | 100111100001010101110… |
… | …1000111000100010001001 |
3 | 201020021012210020020111002 |
4 | 1033002223220320202021 |
5 | 1202443124340032101 |
6 | 15315144045344345 |
7 | 1100300020423454 |
oct | 117025350704211 |
9 | 21207183206432 |
10 | 5431718283401 |
11 | 1804640403713 |
12 | 7388535680b5 |
13 | 305293a75c27 |
14 | 14ac7a27849b |
15 | 96458a09d6b |
hex | 4f0aba38889 |
5431718283401 has 2 divisors, whose sum is σ = 5431718283402. Its totient is φ = 5431718283400.
The previous prime is 5431718283391. The next prime is 5431718283461. The reversal of 5431718283401 is 1043828171345.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3420653949001 + 2011064334400 = 1849501^2 + 1418120^2 .
It is a cyclic number.
It is not a de Polignac number, because 5431718283401 - 222 = 5431714089097 is a prime.
It is not a weakly prime, because it can be changed into another prime (5431718283461) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2715859141700 + 2715859141701.
It is an arithmetic number, because the mean of its divisors is an integer number (2715859141701).
Almost surely, 25431718283401 is an apocalyptic number.
It is an amenable number.
5431718283401 is a deficient number, since it is larger than the sum of its proper divisors (1).
5431718283401 is an equidigital number, since it uses as much as digits as its factorization.
5431718283401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 645120, while the sum is 47.
The spelling of 5431718283401 in words is "five trillion, four hundred thirty-one billion, seven hundred eighteen million, two hundred eighty-three thousand, four hundred one".
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