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54319340929873 is a prime number
BaseRepresentation
bin11000101100111001101010…
…00001010100001101010001
321010022212201021011000211011
430112130311001110031101
524104432002234223443
6311305543303450521
714304304622512345
oct1426346501241521
9233285637130734
1054319340929873
1116342780941918
126113551456a41
1324403a43166c6
14d5b0da60d625
15642e86259b9d
hex316735054351

54319340929873 has 2 divisors, whose sum is σ = 54319340929874. Its totient is φ = 54319340929872.

The previous prime is 54319340929757. The next prime is 54319340929891. The reversal of 54319340929873 is 37892904391345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52342215283264 + 1977125646609 = 7234792^2 + 1406103^2 .

It is a cyclic number.

It is not a de Polignac number, because 54319340929873 - 221 = 54319338832721 is a prime.

It is a super-2 number, since 2×543193409298732 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 54319340929799 and 54319340929808.

It is not a weakly prime, because it can be changed into another prime (54319340929573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27159670464936 + 27159670464937.

It is an arithmetic number, because the mean of its divisors is an integer number (27159670464937).

Almost surely, 254319340929873 is an apocalyptic number.

It is an amenable number.

54319340929873 is a deficient number, since it is larger than the sum of its proper divisors (1).

54319340929873 is an equidigital number, since it uses as much as digits as its factorization.

54319340929873 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 176359680, while the sum is 67.

The spelling of 54319340929873 in words is "fifty-four trillion, three hundred nineteen billion, three hundred forty million, nine hundred twenty-nine thousand, eight hundred seventy-three".