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54323223105433 is a prime number
BaseRepresentation
bin11000101101000000111000…
…11010101000111110011001
321010100020201211010222112011
430112200130122220332121
524110012430103333213
6311311424424145521
714304503052455422
oct1426403432507631
9233306654128464
1054323223105433
111634439326a877
1261142556082a1
1324408726c34c9
14d5b388052649
15643111ea903d
hex31681c6a8f99

54323223105433 has 2 divisors, whose sum is σ = 54323223105434. Its totient is φ = 54323223105432.

The previous prime is 54323223105421. The next prime is 54323223105449. The reversal of 54323223105433 is 33450132232345.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 44592585461824 + 9730637643609 = 6677768^2 + 3119397^2 .

It is a cyclic number.

It is not a de Polignac number, because 54323223105433 - 29 = 54323223104921 is a prime.

It is not a weakly prime, because it can be changed into another prime (54323223105133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27161611552716 + 27161611552717.

It is an arithmetic number, because the mean of its divisors is an integer number (27161611552717).

Almost surely, 254323223105433 is an apocalyptic number.

It is an amenable number.

54323223105433 is a deficient number, since it is larger than the sum of its proper divisors (1).

54323223105433 is an equidigital number, since it uses as much as digits as its factorization.

54323223105433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 777600, while the sum is 40.

Adding to 54323223105433 its reverse (33450132232345), we get a palindrome (87773355337778).

The spelling of 54323223105433 in words is "fifty-four trillion, three hundred twenty-three billion, two hundred twenty-three million, one hundred five thousand, four hundred thirty-three".