Base | Representation |
---|---|
bin | 100111100001101000001… |
… | …1110111000000101111011 |
3 | 201020022210212100200120112 |
4 | 1033003100132320011323 |
5 | 1203000411110322042 |
6 | 15315325250214535 |
7 | 1100321234446613 |
oct | 117032036700573 |
9 | 21208725320515 |
10 | 5432336417147 |
11 | 1804928317752 |
12 | 7389a658444b |
13 | 305361b50643 |
14 | 14acd83c1a43 |
15 | 96492e0a982 |
hex | 4f0d07b817b |
5432336417147 has 2 divisors, whose sum is σ = 5432336417148. Its totient is φ = 5432336417146.
The previous prime is 5432336417141. The next prime is 5432336417191. The reversal of 5432336417147 is 7417146332345.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5432336417147 - 26 = 5432336417083 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5432336417095 and 5432336417104.
It is not a weakly prime, because it can be changed into another prime (5432336417141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2716168208573 + 2716168208574.
It is an arithmetic number, because the mean of its divisors is an integer number (2716168208574).
Almost surely, 25432336417147 is an apocalyptic number.
5432336417147 is a deficient number, since it is larger than the sum of its proper divisors (1).
5432336417147 is an equidigital number, since it uses as much as digits as its factorization.
5432336417147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5080320, while the sum is 50.
The spelling of 5432336417147 in words is "five trillion, four hundred thirty-two billion, three hundred thirty-six million, four hundred seventeen thousand, one hundred forty-seven".
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