Base | Representation |
---|---|
bin | 11000101101001101111011… |
… | …01001000111101010110011 |
3 | 21010100220210122200111000111 |
4 | 30112212331221013222303 |
5 | 24110121244042001433 |
6 | 311314543200202151 |
7 | 14305141400546131 |
oct | 1426467551075263 |
9 | 233326718614014 |
10 | 54330223000243 |
11 | 16347355552403 |
12 | 6115689909357 |
13 | 24414199905b8 |
14 | d5b84d982751 |
15 | 6433c17a1dcd |
hex | 3169bda47ab3 |
54330223000243 has 2 divisors, whose sum is σ = 54330223000244. Its totient is φ = 54330223000242.
The previous prime is 54330223000139. The next prime is 54330223000253. The reversal of 54330223000243 is 34200032203345.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54330223000243 - 213 = 54330222992051 is a prime.
It is a super-2 number, since 2×543302230002432 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (54330223000253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27165111500121 + 27165111500122.
It is an arithmetic number, because the mean of its divisors is an integer number (27165111500122).
Almost surely, 254330223000243 is an apocalyptic number.
54330223000243 is a deficient number, since it is larger than the sum of its proper divisors (1).
54330223000243 is an equidigital number, since it uses as much as digits as its factorization.
54330223000243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 31.
Adding to 54330223000243 its reverse (34200032203345), we get a palindrome (88530255203588).
The spelling of 54330223000243 in words is "fifty-four trillion, three hundred thirty billion, two hundred twenty-three million, two hundred forty-three", and thus it is an aban number.
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