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54331401 = 371255077
BaseRepresentation
bin1100111101000…
…0100000001001
310210020022200010
43033100200021
5102402101101
65220302133
71226544405
oct317204011
9123208603
1054331401
1128739a93
1216241949
13b343a77
147304105
154b832d6
hex33d0809

54331401 has 8 divisors (see below), whose sum is σ = 73462464. Its totient is φ = 35710640.

The previous prime is 54331369. The next prime is 54331421. The reversal of 54331401 is 10413345.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 54331401 - 25 = 54331369 is a prime.

It is a super-2 number, since 2×543314012 = 5903802269245602, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (54331421) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 127326 + ... + 127751.

It is an arithmetic number, because the mean of its divisors is an integer number (9182808).

Almost surely, 254331401 is an apocalyptic number.

It is an amenable number.

54331401 is a deficient number, since it is larger than the sum of its proper divisors (19131063).

54331401 is a wasteful number, since it uses less digits than its factorization.

54331401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 255151.

The product of its (nonzero) digits is 720, while the sum is 21.

The square root of 54331401 is about 7370.9837199657. The cubic root of 54331401 is about 378.7479591215.

Adding to 54331401 its reverse (10413345), we get a palindrome (64744746).

The spelling of 54331401 in words is "fifty-four million, three hundred thirty-one thousand, four hundred one".

Divisors: 1 3 71 213 255077 765231 18110467 54331401