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54331411321 = 11151124926189
BaseRepresentation
bin110010100110011001…
…111000101101111001
312012020110010122221101
4302212121320231321
51342232320130241
640543130411401
73632245243045
oct624631705571
9165213118841
1054331411321
1121050735530
12a643590b61
13517b2396c5
1428b5ab3025
15162ec80e31
hexca6678b79

54331411321 has 16 divisors (see below), whose sum is σ = 59713200000. Its totient is φ = 49023936000.

The previous prime is 54331411313. The next prime is 54331411339. The reversal of 54331411321 is 12311413345.

It is a cyclic number.

It is not a de Polignac number, because 54331411321 - 23 = 54331411313 is a prime.

It is a super-2 number, since 2×543314113212 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 54331411321.

It is not an unprimeable number, because it can be changed into a prime (54331414321) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2061495 + ... + 2087683.

It is an arithmetic number, because the mean of its divisors is an integer number (3732075000).

Almost surely, 254331411321 is an apocalyptic number.

It is an amenable number.

54331411321 is a deficient number, since it is larger than the sum of its proper divisors (5381788679).

54331411321 is a wasteful number, since it uses less digits than its factorization.

54331411321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27600.

The product of its digits is 4320, while the sum is 28.

Adding to 54331411321 its reverse (12311413345), we get a palindrome (66642824666).

The spelling of 54331411321 in words is "fifty-four billion, three hundred thirty-one million, four hundred eleven thousand, three hundred twenty-one".

Divisors: 1 11 151 1249 1661 13739 26189 188599 288079 2074589 3954539 32710061 43499929 359810671 4939219211 54331411321