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54333304413 = 3791153198833
BaseRepresentation
bin110010100110100001…
…000110111001011101
312012020120200211202220
4302212201012321131
51342233311220123
640543235135553
73632300316213
oct624641067135
9165216624686
1054333304413
1121051808873
12a6441445b9
13517b75028b
1428b6046cb3
151630006ce3
hexca6846e5d

54333304413 has 16 divisors (see below), whose sum is σ = 73425419520. Its totient is φ = 35732496384.

The previous prime is 54333304397. The next prime is 54333304429. The reversal of 54333304413 is 31440333345.

54333304413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (54333304397) and next prime (54333304429).

It is not a de Polignac number, because 54333304413 - 24 = 54333304397 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54333304453) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 173845 + ... + 372677.

It is an arithmetic number, because the mean of its divisors is an integer number (4589088720).

Almost surely, 254333304413 is an apocalyptic number.

It is an amenable number.

54333304413 is a deficient number, since it is larger than the sum of its proper divisors (19092115107).

54333304413 is a wasteful number, since it uses less digits than its factorization.

54333304413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 200068.

The product of its (nonzero) digits is 77760, while the sum is 33.

Adding to 54333304413 its reverse (31440333345), we get a palindrome (85773637758).

The spelling of 54333304413 in words is "fifty-four billion, three hundred thirty-three million, three hundred four thousand, four hundred thirteen".

Divisors: 1 3 79 237 1153 3459 91087 198833 273261 596499 15707807 47123421 229254449 687763347 18111101471 54333304413