Base | Representation |
---|---|
bin | 11000101101100010001100… |
… | …00110100011011011010011 |
3 | 21010101221212212002211002112 |
4 | 30112301012012203123103 |
5 | 24110311034200231313 |
6 | 311323542514335535 |
7 | 14306005113531101 |
oct | 1426610606433323 |
9 | 233357785084075 |
10 | 54341102352083 |
11 | 16350a28676478 |
12 | 611780528a5ab |
13 | 24424618c4cb1 |
14 | d5c1a2808c71 |
15 | 64380b95d8a8 |
hex | 316c461a36d3 |
54341102352083 has 2 divisors, whose sum is σ = 54341102352084. Its totient is φ = 54341102352082.
The previous prime is 54341102352079. The next prime is 54341102352091. The reversal of 54341102352083 is 38025320114345.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54341102352083 - 22 = 54341102352079 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 54341102352083.
It is not a weakly prime, because it can be changed into another prime (54341102352283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27170551176041 + 27170551176042.
It is an arithmetic number, because the mean of its divisors is an integer number (27170551176042).
Almost surely, 254341102352083 is an apocalyptic number.
54341102352083 is a deficient number, since it is larger than the sum of its proper divisors (1).
54341102352083 is an equidigital number, since it uses as much as digits as its factorization.
54341102352083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 41.
The spelling of 54341102352083 in words is "fifty-four trillion, three hundred forty-one billion, one hundred two million, three hundred fifty-two thousand, eighty-three".
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