Base | Representation |
---|---|
bin | 100111100010100100010… |
… | …1001110000001101010001 |
3 | 201020112000101001001110011 |
4 | 1033011020221300031101 |
5 | 1203014023222044403 |
6 | 15320301310434521 |
7 | 1100422215246421 |
oct | 117051051601521 |
9 | 21215011031404 |
10 | 5434352534353 |
11 | 1805772372416 |
12 | 739269802a41 |
13 | 3055c374b9c2 |
14 | 14b04a074481 |
15 | 9655ee03a6d |
hex | 4f148a70351 |
5434352534353 has 2 divisors, whose sum is σ = 5434352534354. Its totient is φ = 5434352534352.
The previous prime is 5434352534333. The next prime is 5434352534357. The reversal of 5434352534353 is 3534352534345.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4114925846784 + 1319426687569 = 2028528^2 + 1148663^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5434352534353 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5434352534297 and 5434352534306.
It is not a weakly prime, because it can be changed into another prime (5434352534357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2717176267176 + 2717176267177.
It is an arithmetic number, because the mean of its divisors is an integer number (2717176267177).
Almost surely, 25434352534353 is an apocalyptic number.
It is an amenable number.
5434352534353 is a deficient number, since it is larger than the sum of its proper divisors (1).
5434352534353 is an equidigital number, since it uses as much as digits as its factorization.
5434352534353 is an evil number, because the sum of its binary digits is even.
The product of its digits is 19440000, while the sum is 49.
The spelling of 5434352534353 in words is "five trillion, four hundred thirty-four billion, three hundred fifty-two million, five hundred thirty-four thousand, three hundred fifty-three".
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