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5434352534353 is a prime number
BaseRepresentation
bin100111100010100100010…
…1001110000001101010001
3201020112000101001001110011
41033011020221300031101
51203014023222044403
615320301310434521
71100422215246421
oct117051051601521
921215011031404
105434352534353
111805772372416
12739269802a41
133055c374b9c2
1414b04a074481
159655ee03a6d
hex4f148a70351

5434352534353 has 2 divisors, whose sum is σ = 5434352534354. Its totient is φ = 5434352534352.

The previous prime is 5434352534333. The next prime is 5434352534357. The reversal of 5434352534353 is 3534352534345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4114925846784 + 1319426687569 = 2028528^2 + 1148663^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5434352534353 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5434352534297 and 5434352534306.

It is not a weakly prime, because it can be changed into another prime (5434352534357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2717176267176 + 2717176267177.

It is an arithmetic number, because the mean of its divisors is an integer number (2717176267177).

Almost surely, 25434352534353 is an apocalyptic number.

It is an amenable number.

5434352534353 is a deficient number, since it is larger than the sum of its proper divisors (1).

5434352534353 is an equidigital number, since it uses as much as digits as its factorization.

5434352534353 is an evil number, because the sum of its binary digits is even.

The product of its digits is 19440000, while the sum is 49.

The spelling of 5434352534353 in words is "five trillion, four hundred thirty-four billion, three hundred fifty-two million, five hundred thirty-four thousand, three hundred fifty-three".