Base | Representation |
---|---|
bin | 11000101101111010110101… |
… | …10110010000110110111001 |
3 | 21010110020001002020111002012 |
4 | 30112331122312100312321 |
5 | 24111020134314231040 |
6 | 311334011550415305 |
7 | 14306654046011141 |
oct | 1426753266206671 |
9 | 233406032214065 |
10 | 54354335305145 |
11 | 163565a92a0a17 |
12 | 611a298b01535 |
13 | 244379031b135 |
14 | d5ca9a093921 |
15 | 643d33578865 |
hex | 316f5ad90db9 |
54354335305145 has 16 divisors (see below), whose sum is σ = 65531392455360. Its totient is φ = 43279465368384.
The previous prime is 54354335305111. The next prime is 54354335305157. The reversal of 54354335305145 is 54150353345345.
It is a cyclic number.
It is not a de Polignac number, because 54354335305145 - 222 = 54354331110841 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54354335305093 and 54354335305102.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4227287 + ... + 11250716.
It is an arithmetic number, because the mean of its divisors is an integer number (4095712028460).
Almost surely, 254354335305145 is an apocalyptic number.
It is an amenable number.
54354335305145 is a deficient number, since it is larger than the sum of its proper divisors (11177057150215).
54354335305145 is a wasteful number, since it uses less digits than its factorization.
54354335305145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15481304.
The product of its (nonzero) digits is 16200000, while the sum is 50.
The spelling of 54354335305145 in words is "fifty-four trillion, three hundred fifty-four billion, three hundred thirty-five million, three hundred five thousand, one hundred forty-five".
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