Base | Representation |
---|---|
bin | 110010101000110111… |
… | …011100010010110010 |
3 | 12012100022212001002021 |
4 | 302220313130102302 |
5 | 1342323403314100 |
6 | 40551203542054 |
7 | 3633256304023 |
oct | 625067342262 |
9 | 165308761067 |
10 | 54372713650 |
11 | 21071a85592 |
12 | a65538a92a |
13 | 518696ac58 |
14 | 28bb384c4a |
15 | 16336dda1a |
hex | ca8ddc4b2 |
54372713650 has 12 divisors (see below), whose sum is σ = 101133247482. Its totient is φ = 21749085440.
The previous prime is 54372713639. The next prime is 54372713651. The reversal of 54372713650 is 5631727345.
54372713650 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 3 ways, for example, as 22993779769 + 31378933881 = 151637^2 + 177141^2 .
It is a junction number, because it is equal to n+sod(n) for n = 54372713597 and 54372713606.
It is not an unprimeable number, because it can be changed into a prime (54372713651) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 543727087 + ... + 543727186.
Almost surely, 254372713650 is an apocalyptic number.
54372713650 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
54372713650 is a deficient number, since it is larger than the sum of its proper divisors (46760533832).
54372713650 is a wasteful number, since it uses less digits than its factorization.
54372713650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1087454285 (or 1087454280 counting only the distinct ones).
The product of its (nonzero) digits is 529200, while the sum is 43.
The spelling of 54372713650 in words is "fifty-four billion, three hundred seventy-two million, seven hundred thirteen thousand, six hundred fifty".
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