Base | Representation |
---|---|
bin | 110010101010100001… |
… | …000110001100100011 |
3 | 12012102020222011212221 |
4 | 302222201012030203 |
5 | 1342403001113103 |
6 | 40554033331511 |
7 | 3634043600413 |
oct | 625241061443 |
9 | 165366864787 |
10 | 54400410403 |
11 | 21086682569 |
12 | a662706b97 |
13 | 518c617771 |
14 | 28c0d14643 |
15 | 1635d601bd |
hex | caa846323 |
54400410403 has 2 divisors, whose sum is σ = 54400410404. Its totient is φ = 54400410402.
The previous prime is 54400410377. The next prime is 54400410511. The reversal of 54400410403 is 30401400445.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54400410403 - 29 = 54400409891 is a prime.
It is not a weakly prime, because it can be changed into another prime (54400414403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27200205201 + 27200205202.
It is an arithmetic number, because the mean of its divisors is an integer number (27200205202).
Almost surely, 254400410403 is an apocalyptic number.
54400410403 is a deficient number, since it is larger than the sum of its proper divisors (1).
54400410403 is an equidigital number, since it uses as much as digits as its factorization.
54400410403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 25.
Adding to 54400410403 its reverse (30401400445), we get a palindrome (84801810848).
The spelling of 54400410403 in words is "fifty-four billion, four hundred million, four hundred ten thousand, four hundred three".
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