Base | Representation |
---|---|
bin | 100111100101010110011… |
… | …1101010001110101100011 |
3 | 201021002102222100010120102 |
4 | 1033022230331101311203 |
5 | 1203113244031413411 |
6 | 15323130411533015 |
7 | 1101023312624315 |
oct | 117125475216543 |
9 | 21232388303512 |
10 | 5440330341731 |
11 | 180825a71559a |
12 | 73a45775a16b |
13 | 30603704732c |
14 | 14b455d477b5 |
15 | 967aeb05d3b |
hex | 4f2acf51d63 |
5440330341731 has 2 divisors, whose sum is σ = 5440330341732. Its totient is φ = 5440330341730.
The previous prime is 5440330341713. The next prime is 5440330341799. The reversal of 5440330341731 is 1371430330445.
Together with previous prime (5440330341713) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5440330341731 is a prime.
It is a super-2 number, since 2×54403303417312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5440330341431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2720165170865 + 2720165170866.
It is an arithmetic number, because the mean of its divisors is an integer number (2720165170866).
Almost surely, 25440330341731 is an apocalyptic number.
5440330341731 is a deficient number, since it is larger than the sum of its proper divisors (1).
5440330341731 is an equidigital number, since it uses as much as digits as its factorization.
5440330341731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 38.
The spelling of 5440330341731 in words is "five trillion, four hundred forty billion, three hundred thirty million, three hundred forty-one thousand, seven hundred thirty-one".
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