Base | Representation |
---|---|
bin | 100111100101011000111… |
… | …1001000100011000001111 |
3 | 201021002122202002220122111 |
4 | 1033022301321010120033 |
5 | 1203113431224432421 |
6 | 15323142530124451 |
7 | 1101025336356340 |
oct | 117126171043017 |
9 | 21232582086574 |
10 | 5440413124111 |
11 | 18082a2417189 |
12 | 73a47b420727 |
13 | 30604b23cca4 |
14 | 14b462d360c7 |
15 | 967b7008ee1 |
hex | 4f2b1e4460f |
5440413124111 has 16 divisors (see below), whose sum is σ = 6231161456640. Its totient is φ = 4653053180640.
The previous prime is 5440413124099. The next prime is 5440413124147. The reversal of 5440413124111 is 1114213140445.
It is a cyclic number.
It is not a de Polignac number, because 5440413124111 - 223 = 5440404735503 is a prime.
It is a super-2 number, since 2×54404131241112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5440413124151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 40104580 + ... + 40240006.
It is an arithmetic number, because the mean of its divisors is an integer number (389447591040).
Almost surely, 25440413124111 is an apocalyptic number.
5440413124111 is a deficient number, since it is larger than the sum of its proper divisors (790748332529).
5440413124111 is a wasteful number, since it uses less digits than its factorization.
5440413124111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 147894.
The product of its (nonzero) digits is 7680, while the sum is 31.
Adding to 5440413124111 its reverse (1114213140445), we get a palindrome (6554626264556).
The spelling of 5440413124111 in words is "five trillion, four hundred forty billion, four hundred thirteen million, one hundred twenty-four thousand, one hundred eleven".
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