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54404413051 = 409113298561
BaseRepresentation
bin110010101010110000…
…010111011001111011
312012102112111112111011
4302222300113121323
51342410012204201
640554255214351
73634122611062
oct625260273173
9165375445434
1054404413051
112108896683a
12a663b173b7
1351903b95b1
1428c16771d9
1516363a1151
hexcaac1767b

54404413051 has 4 divisors (see below), whose sum is σ = 54417715704. Its totient is φ = 54391110400.

The previous prime is 54404413043. The next prime is 54404413117. The reversal of 54404413051 is 15031440445.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 54404413051 - 23 = 54404413043 is a prime.

It is a super-4 number, since 4×544044130514 (a number of 44 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54404413031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6645190 + ... + 6653371.

It is an arithmetic number, because the mean of its divisors is an integer number (13604428926).

Almost surely, 254404413051 is an apocalyptic number.

54404413051 is a deficient number, since it is larger than the sum of its proper divisors (13302653).

54404413051 is a wasteful number, since it uses less digits than its factorization.

54404413051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13302652.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 54404413051 its reverse (15031440445), we get a palindrome (69435853496).

The spelling of 54404413051 in words is "fifty-four billion, four hundred four million, four hundred thirteen thousand, fifty-one".

Divisors: 1 4091 13298561 54404413051