Base | Representation |
---|---|
bin | 111101110110110111011111… |
… | …0110100001100011000111010 |
3 | 2122100111200202202112100200222 |
4 | 1323231232332310030120322 |
5 | 1032304034002041444232 |
6 | 5205113131355100042 |
7 | 222415053151014242 |
oct | 17355567664143072 |
9 | 2570450682470628 |
10 | 544102543312442 |
11 | 148405657a80914 |
12 | 51036874a41622 |
13 | 1a47a85a44c1ca |
14 | 98509bc9bcb22 |
15 | 42d8550c43d12 |
hex | 1eedbbed0c63a |
544102543312442 has 8 divisors (see below), whose sum is σ = 835134136247136. Its totient is φ = 265724497896732.
The previous prime is 544102543312411. The next prime is 544102543312507. The reversal of 544102543312442 is 244213345201445.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 544102543312393 and 544102543312402.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3163386879638 + ... + 3163386879809.
It is an arithmetic number, because the mean of its divisors is an integer number (104391767030892).
Almost surely, 2544102543312442 is an apocalyptic number.
544102543312442 is a deficient number, since it is larger than the sum of its proper divisors (291031592934694).
544102543312442 is a wasteful number, since it uses less digits than its factorization.
544102543312442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6326773759492.
The product of its (nonzero) digits is 1843200, while the sum is 44.
Adding to 544102543312442 its reverse (244213345201445), we get a palindrome (788315888513887).
The spelling of 544102543312442 in words is "five hundred forty-four trillion, one hundred two billion, five hundred forty-three million, three hundred twelve thousand, four hundred forty-two".
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