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544106113 is a prime number
BaseRepresentation
bin100000011011100…
…110011010000001
31101220211110021021
4200123212122001
52103242343423
6125554025441
716324553125
oct4033463201
91356743237
10544106113
1125a151a81
12132278281
13889588a5
1452397585
1532b7b95d
hex206e6681

544106113 has 2 divisors, whose sum is σ = 544106114. Its totient is φ = 544106112.

The previous prime is 544106051. The next prime is 544106119. The reversal of 544106113 is 311601445.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 497156209 + 46949904 = 22297^2 + 6852^2 .

It is a cyclic number.

It is not a de Polignac number, because 544106113 - 217 = 543975041 is a prime.

It is not a weakly prime, because it can be changed into another prime (544106119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272053056 + 272053057.

It is an arithmetic number, because the mean of its divisors is an integer number (272053057).

Almost surely, 2544106113 is an apocalyptic number.

It is an amenable number.

544106113 is a deficient number, since it is larger than the sum of its proper divisors (1).

544106113 is an equidigital number, since it uses as much as digits as its factorization.

544106113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

The square root of 544106113 is about 23326.0822471327. The cubic root of 544106113 is about 816.3840949557.

Adding to 544106113 its reverse (311601445), we get a palindrome (855707558).

The spelling of 544106113 in words is "five hundred forty-four million, one hundred six thousand, one hundred thirteen".