Base | Representation |
---|---|
bin | 110010101011001111… |
… | …010101011110101011 |
3 | 12012110002210000002011 |
4 | 302223033111132223 |
5 | 1342414102003002 |
6 | 40555145220351 |
7 | 3634251613306 |
oct | 625317253653 |
9 | 165402700064 |
10 | 54412531627 |
11 | 21092501403 |
12 | a6667916b7 |
13 | 5191c9c99c |
14 | 28c278bb3d |
15 | 1636e568d7 |
hex | cab3d57ab |
54412531627 has 2 divisors, whose sum is σ = 54412531628. Its totient is φ = 54412531626.
The previous prime is 54412531553. The next prime is 54412531651. The reversal of 54412531627 is 72613521445.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54412531627 - 211 = 54412529579 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 54412531627.
It is not a weakly prime, because it can be changed into another prime (54412531697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27206265813 + 27206265814.
It is an arithmetic number, because the mean of its divisors is an integer number (27206265814).
Almost surely, 254412531627 is an apocalyptic number.
54412531627 is a deficient number, since it is larger than the sum of its proper divisors (1).
54412531627 is an equidigital number, since it uses as much as digits as its factorization.
54412531627 is an evil number, because the sum of its binary digits is even.
The product of its digits is 201600, while the sum is 40.
The spelling of 54412531627 in words is "fifty-four billion, four hundred twelve million, five hundred thirty-one thousand, six hundred twenty-seven".
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