Base | Representation |
---|---|
bin | 110010101011010001… |
… | …001011100011010011 |
3 | 12012110010200120111011 |
4 | 302223101023203103 |
5 | 1342414212442001 |
6 | 40555203431351 |
7 | 3634255666300 |
oct | 625321134323 |
9 | 165403616434 |
10 | 54413015251 |
11 | 210928017a1 |
12 | a666985557 |
13 | 519210bb5a |
14 | 28c28760a7 |
15 | 1636eeed51 |
hex | cab44b8d3 |
54413015251 has 48 divisors (see below), whose sum is σ = 68146033536. Its totient is φ = 43163844864.
The previous prime is 54413015249. The next prime is 54413015269. The reversal of 54413015251 is 15251031445.
54413015251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 54413015251 - 21 = 54413015249 is a prime.
It is not an unprimeable number, because it can be changed into a prime (54413010251) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 15692820 + ... + 15696286.
It is an arithmetic number, because the mean of its divisors is an integer number (1419709032).
Almost surely, 254413015251 is an apocalyptic number.
54413015251 is a deficient number, since it is larger than the sum of its proper divisors (13733018285).
54413015251 is a wasteful number, since it uses less digits than its factorization.
54413015251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3808 (or 3801 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 54413015251 its reverse (15251031445), we get a palindrome (69664046696).
The spelling of 54413015251 in words is "fifty-four billion, four hundred thirteen million, fifteen thousand, two hundred fifty-one".
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