Base | Representation |
---|---|
bin | 1111110101100001111… |
… | …10011111010010101011 |
3 | 1221000111201002120112020 |
4 | 13322300332133102223 |
5 | 32403342033103121 |
6 | 1053545554315523 |
7 | 54212113420611 |
oct | 7726076372253 |
9 | 1830451076466 |
10 | 544135050411 |
11 | 19a848061077 |
12 | 89559888ba3 |
13 | 3c408ab8214 |
14 | 1c49ca5b6b1 |
15 | e24a66a1c6 |
hex | 7eb0f9f4ab |
544135050411 has 4 divisors (see below), whose sum is σ = 725513400552. Its totient is φ = 362756700272.
The previous prime is 544135050383. The next prime is 544135050467. The reversal of 544135050411 is 114050531445.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 544135050411 - 210 = 544135049387 is a prime.
It is a super-2 number, since 2×5441350504112 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (544135000411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90689175066 + ... + 90689175071.
It is an arithmetic number, because the mean of its divisors is an integer number (181378350138).
Almost surely, 2544135050411 is an apocalyptic number.
544135050411 is a deficient number, since it is larger than the sum of its proper divisors (181378350141).
544135050411 is a wasteful number, since it uses less digits than its factorization.
544135050411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 181378350140.
The product of its (nonzero) digits is 24000, while the sum is 33.
Adding to 544135050411 its reverse (114050531445), we get a palindrome (658185581856).
The spelling of 544135050411 in words is "five hundred forty-four billion, one hundred thirty-five million, fifty thousand, four hundred eleven".
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