Base | Representation |
---|---|
bin | 110010101011111011… |
… | …100101100110100010 |
3 | 12012110220121100210200 |
4 | 302223323211212202 |
5 | 1342430034211002 |
6 | 41000242010030 |
7 | 3634452326532 |
oct | 625373454642 |
9 | 165426540720 |
10 | 54424132002 |
11 | 21099004999 |
12 | a66a646916 |
13 | 5194501b06 |
14 | 28c412b4c2 |
15 | 1637e98b1c |
hex | cabee59a2 |
54424132002 has 48 divisors (see below), whose sum is σ = 119479389120. Its totient is φ = 17902876896.
The previous prime is 54424132001. The next prime is 54424132033. The reversal of 54424132002 is 20023142445.
54424132002 is a `hidden beast` number, since 5 + 4 + 42 + 413 + 200 + 2 = 666.
It is a super-2 number, since 2×544241320022 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (54424132001) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 352708 + ... + 482960.
It is an arithmetic number, because the mean of its divisors is an integer number (2489153940).
Almost surely, 254424132002 is an apocalyptic number.
54424132002 is an abundant number, since it is smaller than the sum of its proper divisors (65055257118).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
54424132002 is a wasteful number, since it uses less digits than its factorization.
54424132002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 130567 (or 130564 counting only the distinct ones).
The product of its (nonzero) digits is 7680, while the sum is 27.
Adding to 54424132002 its reverse (20023142445), we get a palindrome (74447274447).
The spelling of 54424132002 in words is "fifty-four billion, four hundred twenty-four million, one hundred thirty-two thousand, two".
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