Base | Representation |
---|---|
bin | 111101111000100001101010… |
… | …1001010100001011101000011 |
3 | 2122101022111022001012222112201 |
4 | 1323301003111022201131003 |
5 | 1032321302432143000311 |
6 | 5205410000410334031 |
7 | 222440404334626135 |
oct | 17361032512413503 |
9 | 2571274261188481 |
10 | 544330551531331 |
11 | 148493321742454 |
12 | 51072aa842a317 |
13 | 1a4961c62a6066 |
14 | 985ba4c78d055 |
15 | 42de4480049c1 |
hex | 1ef10d52a1743 |
544330551531331 has 4 divisors (see below), whose sum is σ = 544563270880200. Its totient is φ = 544097832182464.
The previous prime is 544330551531311. The next prime is 544330551531409. The reversal of 544330551531331 is 133135155033445.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 544330551531331 - 231 = 544328404047683 is a prime.
It is a super-2 number, since 2×5443305515313312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (544330551531311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116359670926 + ... + 116359675603.
It is an arithmetic number, because the mean of its divisors is an integer number (136140817720050).
Almost surely, 2544330551531331 is an apocalyptic number.
544330551531331 is a deficient number, since it is larger than the sum of its proper divisors (232719348869).
544330551531331 is a wasteful number, since it uses less digits than its factorization.
544330551531331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 232719348868.
The product of its (nonzero) digits is 2430000, while the sum is 46.
The spelling of 544330551531331 in words is "five hundred forty-four trillion, three hundred thirty billion, five hundred fifty-one million, five hundred thirty-one thousand, three hundred thirty-one".
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