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544333245041 = 1314155215611
BaseRepresentation
bin1111110101111001100…
…10100010101001110001
31221001000112000220110002
413322330302202221301
532404243302320131
61054021354315345
754220041145535
oct7727462425161
91831015026402
10544333245041
1119a939a20693
12895b4128b55
133c43ab8c851
141c4bb0cdbc5
15e25cc696cb
hex7ebcca2a71

544333245041 has 4 divisors (see below), whose sum is σ = 548488460784. Its totient is φ = 540178029300.

The previous prime is 544333245017. The next prime is 544333245073. The reversal of 544333245041 is 140542333445.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 544333245041 - 210 = 544333244017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 544333244986 and 544333245004.

It is not an unprimeable number, because it can be changed into a prime (544333245011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2077607675 + ... + 2077607936.

It is an arithmetic number, because the mean of its divisors is an integer number (137122115196).

Almost surely, 2544333245041 is an apocalyptic number.

It is an amenable number.

544333245041 is a deficient number, since it is larger than the sum of its proper divisors (4155215743).

544333245041 is a wasteful number, since it uses less digits than its factorization.

544333245041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4155215742.

The product of its (nonzero) digits is 345600, while the sum is 38.

Adding to 544333245041 its reverse (140542333445), we get a palindrome (684875578486).

The spelling of 544333245041 in words is "five hundred forty-four billion, three hundred thirty-three million, two hundred forty-five thousand, forty-one".

Divisors: 1 131 4155215611 544333245041