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544423125241451 is a prime number
BaseRepresentation
bin111101111001001100110001…
…0111111001100111001101011
32122101122100020122222201020002
41323302121202333030321223
51032324312030030211301
65205520310410253215
7222450162365316551
oct17362314277147153
92571570218881202
10544423125241451
11148519607131aa5
1251088a2312720b
131a4a1b5a394c21
149862311407bd1
1542e1a652bc16b
hex1ef2662fcce6b

544423125241451 has 2 divisors, whose sum is σ = 544423125241452. Its totient is φ = 544423125241450.

The previous prime is 544423125241357. The next prime is 544423125241477. The reversal of 544423125241451 is 154142521324445.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-544423125241451 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 544423125241396 and 544423125241405.

It is not a weakly prime, because it can be changed into another prime (544423125241481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272211562620725 + 272211562620726.

It is an arithmetic number, because the mean of its divisors is an integer number (272211562620726).

Almost surely, 2544423125241451 is an apocalyptic number.

544423125241451 is a deficient number, since it is larger than the sum of its proper divisors (1).

544423125241451 is an equidigital number, since it uses as much as digits as its factorization.

544423125241451 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3072000, while the sum is 47.

Adding to 544423125241451 its reverse (154142521324445), we get a palindrome (698565646565896).

The spelling of 544423125241451 in words is "five hundred forty-four trillion, four hundred twenty-three billion, one hundred twenty-five million, two hundred forty-one thousand, four hundred fifty-one".