Base | Representation |
---|---|
bin | 110010101101001000… |
… | …010100010100001001 |
3 | 12012112022110021101222 |
4 | 302231020110110021 |
5 | 1343000211340111 |
6 | 41002241051425 |
7 | 3635115312665 |
oct | 625510242411 |
9 | 165468407358 |
10 | 54444246281 |
11 | 210a93a3067 |
12 | a675326b75 |
13 | 5198725259 |
14 | 28c6a858a5 |
15 | 1639b1d7db |
hex | cad214509 |
54444246281 has 2 divisors, whose sum is σ = 54444246282. Its totient is φ = 54444246280.
The previous prime is 54444246239. The next prime is 54444246301. The reversal of 54444246281 is 18264244445.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 45415445881 + 9028800400 = 213109^2 + 95020^2 .
It is a cyclic number.
It is not a de Polignac number, because 54444246281 - 210 = 54444245257 is a prime.
It is a super-3 number, since 3×544442462813 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (54444246221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27222123140 + 27222123141.
It is an arithmetic number, because the mean of its divisors is an integer number (27222123141).
Almost surely, 254444246281 is an apocalyptic number.
It is an amenable number.
54444246281 is a deficient number, since it is larger than the sum of its proper divisors (1).
54444246281 is an equidigital number, since it uses as much as digits as its factorization.
54444246281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 983040, while the sum is 44.
The spelling of 54444246281 in words is "fifty-four billion, four hundred forty-four million, two hundred forty-six thousand, two hundred eighty-one".
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