Base | Representation |
---|---|
bin | 1111110110000110110… |
… | …10101001111110110001 |
3 | 1221001022021020101110111 |
4 | 13323003122221332301 |
5 | 32410010233032423 |
6 | 1054040405301321 |
7 | 54222561151012 |
oct | 7730332517661 |
9 | 1831267211414 |
10 | 544444424113 |
11 | 19a996758117 |
12 | 89625404841 |
13 | 3c457c18795 |
14 | 1c4cbb91009 |
15 | e2678cb60d |
hex | 7ec36a9fb1 |
544444424113 has 2 divisors, whose sum is σ = 544444424114. Its totient is φ = 544444424112.
The previous prime is 544444424107. The next prime is 544444424143. The reversal of 544444424113 is 311424444445.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 287240258704 + 257204165409 = 535948^2 + 507153^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-544444424113 is a prime.
It is not a weakly prime, because it can be changed into another prime (544444424143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 272222212056 + 272222212057.
It is an arithmetic number, because the mean of its divisors is an integer number (272222212057).
Almost surely, 2544444424113 is an apocalyptic number.
It is an amenable number.
544444424113 is a deficient number, since it is larger than the sum of its proper divisors (1).
544444424113 is an equidigital number, since it uses as much as digits as its factorization.
544444424113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 491520, while the sum is 40.
Adding to 544444424113 its reverse (311424444445), we get a palindrome (855868868558).
The spelling of 544444424113 in words is "five hundred forty-four billion, four hundred forty-four million, four hundred twenty-four thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •