Base | Representation |
---|---|
bin | 110010101101001100… |
… | …000100100010100001 |
3 | 12012112101022021010221 |
4 | 302231030010202201 |
5 | 1343000434331431 |
6 | 41002314123041 |
7 | 3635126551453 |
oct | 625514044241 |
9 | 165471267127 |
10 | 54445230241 |
11 | 210a9a05356 |
12 | a675720481 |
13 | 51989ab08c |
14 | 28c6c602d3 |
15 | 1639c65111 |
hex | cad3048a1 |
54445230241 has 4 divisors (see below), whose sum is σ = 54446218432. Its totient is φ = 54444242052.
The previous prime is 54445230223. The next prime is 54445230247. The reversal of 54445230241 is 14203254445.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 54445230241 - 25 = 54445230209 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 54445230197 and 54445230206.
It is not an unprimeable number, because it can be changed into a prime (54445230247) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 406245 + ... + 523378.
It is an arithmetic number, because the mean of its divisors is an integer number (13611554608).
Almost surely, 254445230241 is an apocalyptic number.
It is an amenable number.
54445230241 is a deficient number, since it is larger than the sum of its proper divisors (988191).
54445230241 is an equidigital number, since it uses as much as digits as its factorization.
54445230241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 988190.
The product of its (nonzero) digits is 76800, while the sum is 34.
Adding to 54445230241 its reverse (14203254445), we get a palindrome (68648484686).
The spelling of 54445230241 in words is "fifty-four billion, four hundred forty-five million, two hundred thirty thousand, two hundred forty-one".
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